Adaptions for fatfs R0.12b

[z180-stamp.git] / time / iso_week_date_r.c

/*
 * (c)2012 Michael Duane Rice All rights reserved.
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 * form must reproduce the above copyright notice, this list of conditions
 * and the following disclaimer in the documentation and/or other materials
 * provided with the distribution. Neither the name of the copyright holders
 * nor the names of contributors may be used to endorse or promote products
 * derived from this software without specific prior written permission.
 *
 * THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS "AS IS"
 * AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
 * ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT OWNER OR CONTRIBUTORS BE
 * LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR
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/* $Id: iso_week_date_r.c 2394 2013-05-04 10:26:24Z swfltek $ */

/*
    Compute the ISO 8601 week date corresponding to the given year and day of year.
    See http://en.wikipedia.org/wiki/ISO_week_date for a full description. To summarize:

        Weeks are numbered from 1 to 53.
        Week days are numbered 1 to 7, beginning with Monday as day 1.

        The first week of the year contains the first Thursday in that year.
        Dates prior to week 1 belong to the final week of the previous year.

        The final week of the year contains the last Thursday in that year.
        Dates after the final week belong to week 1 of the following year.

*/

#include <time.h>

void
iso_week_date_r(int y, int yday, struct week_date * iso)
{
    uint16_t        years, n, wday;
    int             weeknum;
    int isLeap;

    iso->year = y;

    isLeap = is_leap_year(y);

    /* compute days elapsed since epoch */
    years = y - 2000;
    n = 365 * years + yday;
    if (years) {
        n++;        /* epoch was a leap year */
        n += years / 4;
        n -= isLeap;
        if (years > 100)
            n--;
    }

    /* compute ISO8601 day of week (1 ... 7, Monday = 1) */
    wday = n + 6; /* epoch was a Saturday */
    wday %= 7;
    if (wday == 0)
        wday = 7;

    iso->day = wday;

    /* compute tentative week number */
    weeknum = yday + 11 - wday;
    weeknum /= 7;

    /* if 53, it could be week 1 of the following year */
    if (weeknum == 53) {
        /*
            The final week must include its Thursday in the year. We determine the yday of this
            weeks Thursday, and test whether it exceeds this years length.
        */

        /* determine final yday of this year, 364 or 365 */
        n = 364 + isLeap;

        /* compute yday of this weeks Thursday */
        wday--;       /* convert to zero based week, Monday = 0 */
        yday -= wday; /* yday of this weeks Monday */
        yday += 3;    /* yday of this weeks Thursday */

        /* Is this weeks Thursday included in the year? */
        if (yday > (int) n) {
            iso->year++;
            weeknum = 1;
        }
    }
    iso->week = weeknum;

    /*
        If zero, it is the final week of the previous year.
        We determine that by asking for the week number of Dec 31.
    */
    if (weeknum == 0) {
        y = y - 1;
        iso_week_date_r(y, 364 + is_leap_year(y), iso);
        iso->day = wday;
    }
}